Appendices

Pandemic / climate / Earth data

all numbers are in millions

Année	Pandemic deaths	Climate deaths	Earthquake deaths	Birth	death following events	Classics death	World population
2020	4			150,0	4,0	58,9	7 646,0
2021	7			145,3	7,0	59,5	7 725,4
2022	11			139,1	11,0	60,0	7 794,0
2023	145			132,5	145,0	59,5	7 721,5
2024	230			123,5	230,0	58,2	7 555,5
2025	240			120,9	240,0	56,8	7 378,3
2026	320			110,7	320,0	54,8	7 112,1
2027	340			113,8	340,0	52,6	6 831,1
2028	280			116,1	280,0	50,9	6 614,7
2029	210			112,4	210,0	49,8	6 466,2
2030	120	6		122,9	126,0	49,4	6 413,3
2031	60	12		121,9	72,0	49,4	6 413,7
2032	31	22		121,9	53,0	49,5	6 433,2
2033	21	45		122,2	66,0	49,6	6 439,9
2034	12	60		109,5	72,0	49,5	6 427,8
2035	7	70		104,1	77,0	49,3	6 405,4
2036	2	75		102,5	77,0	49,1	6 381,6
2037	1	79		95,7	80,0	48,9	6 348,2
2038		90		87,6	90,0	48,5	6 296,9
2039		102		83,1	102,0	48,0	6 229,5
2040		108	24	78,5	132,0	47,2	6 128,1
2041		110	29	76,0	139,0	46,3	6 017,9
2042		125	34	66,2	159,0	45,3	5 878,7
2043		135	39	60,0	174,0	44,0	5 719,4
2044		140	46	56,1	186,0	42,7	5 545,4
2045		150	52	53,2	202,0	41,2	5 354,0
2046		151	57	45,0	208,0	39,7	5 149,7
2047		154	65	35,0	219,0	37,9	4 926,1
2048		158	75	30,5	233,0	36,1	4 685,7
2049		168	84	25,3	252,0	34,1	4 422,9
2050		174	91	17,7	265,0	31,9	4 141,5
2051		181	99	14,1	280,0	29,6	3 843,7
2052		187	107	9,2	294,0	27,2	3 529,4
2053		198	115	7,1	313,0	24,6	3 196,2
2054		200	106	1,3	306,0	22,1	2 866,9
2055		212	100	1,7	312,0	19,5	2 534,6
2056		224	93	1,0	317,0	16,9	2 199,1
2057		237	83	0,4	320,0	14,3	1 862,6
2058		242	73	1,9	315,0	11,8	1 535,1
2059		257	63	1,5	320,0	9,3	1 204,8
2060		262	58	1,2	320,0	6,8	876,7
2061		277	48	0,9	325,0	4,2	545,9

E = mc$^{2}$ ?

The following demonstration aims to determine the frequency with respect to the mass to be sent into the large machine.

is justifiable as follows, in 3 points: on the one hand, we know via the formulas of special relativity that:

$m^\prime= \frac{1}{\sqrt(1-\frac{v^2}{c^2})}$

Moreover, by differentiating the mass with respect to the speed, we obtain: $\frac{\partial m^\prime}{\partial v} = \frac{dm^\prime}{dv} = -\frac{1}{2}m(1-\frac{v^2}{c^2})^\frac{3}{2} \cdot \frac{d}{dv} (1-\frac{v^2}{c^2})$

which is therefore equal to $(1 - \frac{v^2}{c^2})^\frac{-3}{2} \cdot \frac{2v}{c^2}$ soit $\frac{mv}{c^2(1-\frac{v^2}{c^2}})^\frac{3}{2}$​

On the other hand, we know that $\frac{\partial m^\prime}{\partial v} = m^\prime \cdot \frac{v}{c^2-v^2}$

that is $m^\prime = \frac{\partial m^\prime}{\partial v} \cdot \frac{c^2-v^2}{v}$

Finally, in terms of momentum and Force

$P = m^\prime \cdot v$ et $F = \frac{\partial P}{\partial t} = m^\prime \cdot \frac{\partial v}{\partial t} + v \cdot \frac{\partial m^\prime}{\partial t}$

we therefore obtain that: $F = \frac{\partial m^\prime}{\partial v} \cdot \frac{c^2-v^2}{v} \cdot \frac{\partial v}{\partial t} + v \frac{\partial m^\prime}{\partial t}$

and this is: $F = \frac{1}{\partial t} \cdot (\frac{\partial m^\prime \cdot (c^2 - v^2)}{v} + v \cdot \partial m^\prime)$

from where $F \partial x = \frac{\partial x}{\partial t} ( \frac{\partial m^\prime \cdot (c^2 - v^2)}{v} + v \cdot \partial m^\prime ) = c^2 \cdot \partial m^\prime$$\int_{Dom} F \mathrm{d}x = \int_{Dom^\prime} c^2 \mathrm{d}m^\prime$

either finally $E = \gamma m c^2$

$E$ — energy ;

$k$ = 1,380649×10⁻²³ J/K — Boltzmann constant;

$c$ = 299792458 m/s — speed of light in vacuum ;

$\lambda$ — wave length ;

$v$ — frequency ;

$\hbar$ = 6,62607015·10⁻³⁴ J·s — Planck's constant.

$1 eV$ = (e/C) J = 1,602176565(35)·10$^{-19}$ J $e$ = 1,602176565(35)·10$^{-19}$C — elementary charge.

In addition, the frequency of sending is obtained via the relation: $E = mc^2 = \hbar \frac{c}{\lambda}$ avec $c = \sqrt{\frac{E}{m}}$

$$\lambda = m \cdot \frac{\hbar}{c}$$

with or finally: the frequency is therefore proportional to the mass.

​